Practicing Success
Practicing Success
CUET Preparation Today
PA and PB are two tangents from a point P outside the circle with centre O at the points A and B on it. If ∠APB = 130°, then ∠OAB is equal to: |
45° 50° 35° 65° |
65° |
\(\angle\)OAB = \(\angle\)OBA = \(\frac{1}{2}\) x \(\angle\)APB = \(\angle\)OAB = \(\frac{1}{2}\) x 130 = \({65}^\circ\) Therefore, \(\angle\)OAB is \({65}^\circ\). |
