Practicing Success
If \(\sqrt {x}\) + \(\frac{1}{\sqrt {x}}\) = 3, then find the value of x2 (x2 - 47). |
0 2 -1 -2 |
-1 |
Given, \(\sqrt {x}\) + \(\frac{1}{\sqrt {x}}\) = 3 After squaring ⇒ ⇒ x + \(\frac{1}{x}\) = 32 - 2 = 7 ⇒ x2 + \(\frac{1}{x^2}\) = 72 - 2 = 47 Put value of 47 in ⇒ x2 (x2 - 47)) ⇒ x2 (x2 - x2 - \(\frac{1}{x^2}\)) = x2 × (-) \(\frac{1}{x^2}\) = -1 |