A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolution in 44 seconds, what is the magnitude and direction of acceleration of the stone-
Answer & explanation
Correct answer: option 2
\(a_r = w^2r = (2 \pi n)^2 r \)
\(a_r = (2 \pi \frac{1}{2})^2 (1)\) = π2 ms–2
aT = 0