Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

System of Particle and Rotational Motion

Question:

A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolution in 44 seconds, what is the magnitude and direction of acceleration of the stone-

Options:

π2 ms–2 and direction along the tangent to the circle

π2 ms–2  and direction along the radius towards the centre.

π2 /4 ms–2  and direction along the radius towards the centre.

π2 ms–2  and direction along the radius away from the centre.

Correct Answer:

π2 ms–2  and direction along the radius towards the centre.

Explanation:

\(a_r = w^2r = (2 \pi n)^2 r \)

\(a_r = (2 \pi \frac{1}{2})^2 (1)\) = π2 ms–2 

aT = 0