Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Organic: Haloalkanes and Haloarenes

Question:

What will be the hybridization of highlighted carbon in the given haloarene

Options:

\(sp^2\)

\(sp^3\)

\(sp\)

\(sp^3d\)

Correct Answer:

\(sp^2\)

Explanation:

The carbon atom in a haloarene is \(sp^2\) hybridized. This is because a haloarene is an aromatic compound, and the carbon atoms in an aromatic ring are all \(sp^2\) hybridized.

\(sp^2\) hybridization occurs when three s orbitals and one p orbital on a carbon atom hybridize to form four \(sp^2\) hybrid orbitals. These \(sp^2\) hybrid orbitals are arranged in a trigonal planar geometry, with \(120^o\) bond angles.

The carbon atom in a haloarene forms three bonds with other atoms: two bonds to other carbon atoms in the aromatic ring, and one bond to the halogen atom. The remaining p orbital on the carbon atom does not hybridize, and it overlaps with the p orbitals of the other carbon atoms in the ring to form a \(\pi \) bond system.

The pi bond system is responsible for the aromatic properties of haloarenes. It also makes the carbon atom in the haloarene more stable and less reactive than a carbon atom in an alkane or alkene.

Here is a diagram of the hybridization of carbon in a haloarene: