Consider two inductor circuits. Assume that the current is increasing with time equally in both the circuits.
The correct graph for energy stored in inductor with current is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2)
The energy stored in an inductor carrying current \( I \) is
\( \displaystyle U = \frac{1}{2}LI^{2} \)
So \( U \propto I^{2} \): each graph is a parabola through the origin, rising faster and faster as \( I \) grows. At the same current the energy is proportional to \( L \).
\( L_1 = 10\,\mathrm{mH} \)
\( L_2 = 20\,\mathrm{mH} \)
\( U_2 = 2U_1 \text{ at every value of } I \)
So the 20 mH curve rises more steeply and lies above the 10 mH curve, as in Option (2).
NCERT (2026-27):
Self-Inductance – “… This work done is stored as magnetic potential energy. … Thus, the energy required to build up the current I is,
\( \displaystyle W = \frac{1}{2}LI^{2} \qquad (6.17) \)”