\(A\) and \(B\) throw dice. The probability that \(A's\) throw is greater than \(B's\) throw is

\(\frac{1}{2}\) \(\frac{5}{6}\) \(\frac{5}{12}\) \(\frac{7}{12}\)

\(\frac{5}{12}\)

\(\begin{aligned}\text{Required probability }&=\frac{5+4+3+2+1}{36}\\ &=\frac{5}{12}\end{aligned}\)