Two cards are drawn successively with replacement from a well-shuffled pack of 52 cards, then probability distribution of number of Aces is :

x 0 1 2 P(x) $\frac{144}{169}$ $\frac{24}{169}$ $\frac{1}{169}$ x 0 1 2 P(x) $\frac{1}{169}$ $\frac{2}{169}$ $\frac{4}{169}$ x 0 1 2 P(x) $\frac{1}{4}$ $\frac{2}{4}$ $\frac{3}{4}$ x 0 1 2 P(x) $\frac{1}{169}$ $\frac{24}{169}$ $\frac{144}{169}$

x 0 1 2 P(x) $\frac{144}{169}$ $\frac{24}{169}$ $\frac{1}{169}$