Two chords AB and CD of a circle with centre O intersect each other at P. If ∠AOD = 120° and ∠BOD = 50°, then the value of ∠APC is?
Answer & explanation
Correct answer: option 3
∠AOD = 120°
∠ACD = \(\frac{1}{2}∠AOD\)
∠ACD = 60° = ∠ACP
∠BOC = 50°
∠CAB = \(\frac{1}{2}∠BOC\) = 25° = ∠CAP
Now, in ΔACP
∠APC = 180° - (∠ACP + ∠CAP)
∠APC = 180° - (60° + 25°)
= 180° - 85°
∠APC = 95°