The degree of differential equation $\frac{d^2y}{dx^2} + \left( \frac{dy}{dx} \right)^3 + 6y^5 = 0$ is

1

The correct answer is Option (1) → 1 ##

$\frac{d^2y}{dx^2} + \left( \frac{dy}{dx} \right)^3 + 6y^5 = 0$

We know that, the degree of a differential equation is exponent of highest order derivative.

Highest order derivative is $\frac{d^2y}{dx^2}$.

$∴\text{Degree} = 1$