The ratio of efficiencies of A and B is 3 : 7, A takes 48 days more than B to complete a work. If they work together, in how many days, will the work be completed? |
12 \(\frac{2}{5}\) days 12 days 16 \(\frac{1}{5}\) days 16 \(\frac{3}{5}\) days |
12 days |
Time taken ∝ \(\frac{1}{efficiency}\) A : B ratio of efficiency 3 : 7 time taken 7 : 3 ⇒ difference 4R = 48 R = 12 Total work = (3 + 7) 12 = 120 Efficiency of A & B together = 10 Time taken by A and B = \(\frac{Total\; work}{Efficiency}\) = \(\frac{120}{10}\) = 12 days |