A and B together can complete a work in 20 days. A is 20 percent more efficient than B, B alone can complete the same work in how many days?
Answer & explanation
Correct answer: option 3
A + B = 20 days,
Given,
A is 20 percent more efficient than B,Therefore
A : B
6 : 5
⇒ Therefore, Total work = (6 + 5) x 20 = 11 x 20 = 220 units. ..(Efficiency × Days = Total work)
⇒ Time required by B to complete the work alone = \(\frac{220}{5}\) = 44 days ..(\(\frac{Work}{Efficiency}\) = Time)