If sinA =\(\frac{20}{101}\) . Then find the value of 4cotA .

\(\frac{99}{5}\) \(\frac{99}{4}\) \(\frac{99}{7}\) \(\frac{9}{5}\)

\(\frac{99}{5}\)

sinA =\(\frac{20}{101}\) =\(\frac{P}{H}\)   [ Triplet 20 , 99 , 101 ] B = 99 ⇒ 4cotA = 4 × \(\frac{B}{P}\) = 4 × \(\frac{99}{20}\) = \(\frac{99}{5}\)