If sinA =\(\frac{20}{101}\) . Then find the value of 4cotA .
Answer & explanation
Correct answer: option 1
sinA =\(\frac{20}{101}\) =\(\frac{P}{H}\) [ Triplet 20 , 99 , 101 ]
B = 99
⇒ 4cotA = 4 × \(\frac{B}{P}\)
= 4 × \(\frac{99}{20}\)
= \(\frac{99}{5}\)