Match List-I with List-II

Choose the correct answer from the options given below:

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

The correct answer is option 1. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A) \([Ni(CN)_4]^{2-}\) - This is a complex ion with four cyanide ligands. It's a strong field ligand, so it's likely to cause pairing of electrons in the d-orbitals of the nickel ion.

(B) Bidentate - A bidentate ligand can bond to a central metal atom through two donor atoms.

(C) Chelate ligand - A chelate ligand is a type of ligand that can bond to a central metal atom through multiple donor atoms, forming a ring-like structure.

(D) \([Ni(Cl)_4]^{2-}\) - This is a complex ion with four chloride ligands. Chloride is also a strong field ligand.

Now, let us match these with the properties:

(I) \(EDTA^{4-}\) - EDTA is a hexadentate ligand, which means it can form six bonds with a central metal atom, making it a chelate ligand.

(II) Paramagnetic - Paramagnetic substances have unpaired electrons, typically found in compounds where the metal ion is not fully paired due to the ligands' influence.

(III) Diamagnetic - Diamagnetic substances have all paired electrons, typically found in compounds where the metal ion is fully paired due to the ligands' influence.

(IV) Oxalate - Oxalate is a bidentate ligand because it can form two bonds with a central metal atom.

So, the correct option is: (1) (A)-(II), (B)-(IV), (C)-(I), (D)-(III)