Rohit walks 16 km towards north. From there he walks 8 km towards South. Then, he walks 6 km towards East. How far and in which direction is he with reference to his starting point?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 10 Km North-East
Walks in opposite directions cancel in part, so the north and south walks are combined first; the remaining north and east distances then form a right triangle with the straight-line distance as its hypotenuse.
North–south: \(16-8=8\,\mathrm{km}\) north of the start
East: \(6\,\mathrm{km}\)
Distance \(=\sqrt{8^2+6^2}=\sqrt{100}=10\,\mathrm{km}\)
He is north and east of the starting point, so he is 10 km to the North-East.
