Two fair dice are rolled simultaneously. It is found that one of them shows odd prime numbers. The probability that remaining dice also shows an odd prime number, is equal to |
1/3 $\frac{2}{5}$ $\frac{3}{5}$ None of these |
1/3 |
The correct answer is OPTION 1 - 1/3 First, odd prime numbers on a die are:
So odd prime numbers on a die = {3, 5} → 2 numbers out of 6. The question says:
For the second die:
Thus, Probability= 2/6 = 1/3 |