Find the average of cubes of first 7 consecutive natural numbers.

112 110 116 113

112

Use the formula; Average of cube of first n consecutive natural numbers = \(\frac{n(n+1)^2}{4}\) Here, n = 7 ⇒ Average = \(\frac{7(7+1)^2}{4}\) = \(\frac{7 × 64}{4}\) = 112