Find the average of cubes of first 7 consecutive natural numbers.
Answer & explanation
Correct answer: option 1
Use the formula;
Average of cube of first n consecutive natural numbers = \(\frac{n(n+1)^2}{4}\)
Here, n = 7
⇒ Average = \(\frac{7(7+1)^2}{4}\) = \(\frac{7 × 64}{4}\) = 112