A number is first increased by $16\frac{2}{3}\%$ and then decreased by 15% to get 238. What is 37.5% of that number?
Answer & explanation
Correct answer: option 4
Let initial number = x
16\(\frac{2}{3}\)% = \(\frac{1}{6}\) , 15% = \(\frac{3}{20}\) , 37.5% = \(\frac{3}{8}\)
According to question ,
x × \(\frac{7}{6}\) × \(\frac{17}{20}\) = 238
x = 238 × \(\frac{20}{17}\) × \(\frac{6}{7}\)
x = 240
Now ,
37.5% of 240 = \(\frac{3}{8}\) × 240 = 90