A number is first increased by $16\frac{2}{3}\%$ and then decreased by 15% to get 238. What is 37.5% of that number?

90

Let initial number  = x

16\(\frac{2}{3}\)% = \(\frac{1}{6}\) , 15% = \(\frac{3}{20}\) , 37.5% = \(\frac{3}{8}\)

According to question ,

x × \(\frac{7}{6}\) × \(\frac{17}{20}\)  = 238

x = 238 × \(\frac{20}{17}\) × \(\frac{6}{7}\)

x = 240

Now ,

37.5% of 240 = \(\frac{3}{8}\) × 240 = 90