Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If (x + 6y) = 8, and xy = 2, where x>0, what is the value of (x3 + 216y3)?

Options:

288

224

368

476

Correct Answer:

224

Explanation:

If (x + 6y) = 8

xy = 2

what is the value of (x3 + 216y3)

If (x + 6y) = 8

(x3 + 216y3) = 83 - 3 × 8  × 2  × 6  = 224