$p→ n+v+ A$
In this nuclear reaction A is a/an:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → positron
$P→n+v+e^+$ [Beta-plus decay reaction]
where,
P = Proton
n = Neutron
v = neutrino
$e^+$ = positron
$p→ n+v+ A$
In this nuclear reaction A is a/an:
Correct answer: option 3
The correct answer is Option (3) → positron
$P→n+v+e^+$ [Beta-plus decay reaction]
where,
P = Proton
n = Neutron
v = neutrino
$e^+$ = positron