An aqueous solution of salt contains \(20 g\) of \(NaCl\) per liter. The pressure of the solution at \(35^oC\) will be |
\(8.622 atm\) \(7.398 atm\) \(2.79 atm\) \(4.43 atm\) |
\(8.622 atm\) |
The correct answer is option 1. \(8.622 atm\). Given, Concentration, \(C = 20 g\) of \(NaCl\) per liter or, \(C = \frac{20}{58.44}mol/L\) Temperature, \(T = 35^oC \text{ = }35 + 273 = 308 K\) Gas constant, \(R = 0.0821 L\text{ atm K}^{-1}\text{ mol}^{-1}\) We know, for osmotic pressure, \(\pi = CRT\) where, [\(\pi \) is osmotic pressure ] or, \(\pi = \frac{20}{58.44} × 0.0821 × 308\) or, \(\pi ≈ 8.622 atm\) |