The integral $∫\frac{dx}{\sqrt{\frac{1}{2}-5x-x^2}}$ is equal to :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\sin^{-1}\frac{2x+5}{3\sqrt{3}}+C$
$I=∫\frac{dx}{\sqrt{\frac{1}{2}-5x-x^2}}$
$∫\frac{dx}{\sqrt{\frac{27}{4}-(x+\frac{5}{2})^2}}$
$=\sin^{-1}(\frac{x+\frac{5}{2}}{\frac{3\sqrt{3}}{2}})+C$
$=\sin^{-1}(\frac{2x+5}{3\sqrt{3}})+C$