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ΔABC is a right angled triangle, ∠C - 90 degree, Ab = 25 cm and BC = 20 cm. What is the value of sec A ? |
$\frac{5}{3}$ $\frac{4}{5}$ $\frac{4}{3}$ $\frac{5}{4}$ |
$\frac{5}{3}$ |
We have, AB = 25 cm, BC = 20 cm ∠C = 90°, Using Pythagoras Theorem AC = \(\sqrt {(AB^2 – BC^2)}\) AC = \(\sqrt {(25^2 – 20^2)}\) = 15 cm = sec A = \(\frac{ AC }{ BC }\) = \(\frac{ 25 }{ 15 }\) = \(\frac{ 5 }{ 3 }\) |
