ΔABC is a right angled triangle, ∠C - 90 degree, Ab = 25 cm and BC = 20 cm. What is the value of sec A ?
Answer & explanation
Correct answer: option 1
We have,
AB = 25 cm,
BC = 20 cm
∠C = 90°,
Using Pythagoras Theorem
AC = \(\sqrt {(AB^2 – BC^2)}\)
AC = \(\sqrt {(25^2 – 20^2)}\) = 15 cm
= sec A = \(\frac{ AC }{ BC }\) = \(\frac{ 25 }{ 15 }\) = \(\frac{ 5 }{ 3 }\)