A transistor having $α$ = 0.99, is used in a common-base amplifier. If the load resistance is 4.5 KΩ and the dynamic resistance of the emitter junction is 50 KΩ, the voltage gain of the amplifier will be:
Answer & explanation
Correct answer: option 2
$\frac{αR_L}{R_e}=\frac{0.99×4500}{50}=89.1$