Complete the series: 59049, 6561, ?, 81, 9, 1
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 729
The series ends in 81, 9, 1, so it runs down the powers of 9: each term is the one before it divided by 9.
\(59049=9^5\)
\(6561=9^4\)
\(?=9^3=729\)
\(81=9^2\), \(9=9^1\), \(1=9^0\)