The number of chloride ions produced by the complex tetraamminechloroplatinum (IV) chloride in an aqueous solution is |
1 2 3 4 |
2 |
The correct answer is option 2. 2. The complex tetraamminechloroplatinum (IV) chloride dissociates in aqueous solution to form two chloride ions. The chemical formula for the complex is \([Pt(NH_3)_4Cl_2]Cl_2\), and the dissociation equation is as follows: \([Pt(NH_3)_4Cl_2]Cl_2 + 2H_2O → [Pt(NH_3)_4(H_2O)_2]^{2+} + 2Cl^-\) Therefore, the number of chloride ions produced by the complex in an aqueous solution is two. The correct answer is 2. |