xFe + yH2O → Fe3O4 + zH2 What is the value of x, y and z respectively in the balanced reaction? |
2, 4 and 4 3, 4 and 4 3, 5 and 4 3, 4 and 6 |
3, 4 and 4 |
The correct answer is option 2. 3, 4 and 4. Let us balance the chemical equation step-by-step to find the values of x, y, and z: Balance Iron (Fe): We see one Fe on the reactant side and three Fe on the product side. To balance \(Fe\), we need to put a coefficient of 3 before Fe on the reactant side: \(3Fe + yH_2O \longrightarrow Fe_3O_4 + zH_2\) Balance Oxygen (O): Now, there are 4 \(O\) on the product side (from \(Fe_3O_4\)) and only 1 \(O\) on the reactant side (from \(H_2O\)). To balance oxygen, we need a coefficient of 4 before \(H_2O\) on the reactant side: \(3Fe + 4H_2O \longrightarrow Fe_3O_4 + zH_2\) Balance Hydrogen (H): Finally, we have 8 \(H\) atoms on the reactant side (from \(4H_2O\)) and only 2 \(H\) atoms on the product side (from \(H_2\)). To balance hydrogen, we need a coefficient of 4 before \(H_2\) on the product side: \(3Fe + 4H_2O \longrightarrow Fe_3O_4 + 4H_2\) Therefore, the balanced equation is: \(3Fe + 4H_2O \longrightarrow Fe_3O_4 + 4H_2\) So the values are: \(x\) (number of \(Fe\) atoms) = \(3\) \(y\) (number of \(H_2O\) molecules) = \(4\) \(z\) (number of \(H_2\) molecules) = \(4\) |