Practicing Success
Practicing Success
CUET Preparation Today
The slope of tangent to the curve $x=t^2+3 t-8, y=2 t^2-2 t-5$ at the point (2, -1) is: |
$\frac{22}{7}$ $\frac{-6}{7}$ $\frac{7}{6}$ $\frac{6}{7}$ |
$\frac{6}{7}$ |
The correct answer is Option (4) → $\frac{6}{7}$ |
