What is the slope of the graph drawn bet

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Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

What is the slope of the graph drawn between frequency of incident light and stopping potential for a given surface?

Options:

$h$

$he^{-1}$

$eh$

$e$

Correct Answer:

$he^{-1}$

Explanation:

$ eV_s = h\nu - \phi$

$ V_s = \frac{h}{e} \nu - \frac{\phi}{e}$

slope is he^-1

The correct answer is Option (2) → $he^{-1}$