A man driving at \(\frac{3}{4}\)th of his original speed reaches his destination 20 minutes later than the usual time . The usual time is :

80 min 60 min 75 min 60 min

60 min

Reduces his speed to \(\frac{3}{4}\) times Ratio             Initial   :     New   Speed             4     :      3  Time               3     :      4 According to question ,  1R = 20 min 3R = 60 min