A man driving at \(\frac{3}{4}\)th of his original speed reaches his destination 20 minutes later than the usual time . The usual time is :
Answer & explanation
Correct answer: option 2
Reduces his speed to \(\frac{3}{4}\) times
Ratio Initial : New
Speed 4 : 3
Time 3 : 4
According to question , 1R = 20 min
3R = 60 min