If the radius of a sphere is increased by 33.33%, its volume is increased by how much percent? -
Answer & explanation
Correct answer: option 1
New radius = \(\frac{4}{3}\) r( i.e.original radius)
Changed Volume = \(\frac{4}{3}\) \(\pi\) (\(\frac{4}{3}\) r)³ = \(\frac{4}{3}\) \(\pi \) \(\frac{64}{27}\) r³ = 137.03% increase