CUET Preparation Today
If the radius of a sphere is increased by 33.33%, its volume is increased by how much percent? - |
137.03% 100% 33.33% no change |
137.03% |
New radius = \(\frac{4}{3}\) r( i.e.original radius) Changed Volume = \(\frac{4}{3}\) \(\pi\) (\(\frac{4}{3}\) r)³ = \(\frac{4}{3}\) \(\pi \) \(\frac{64}{27}\) r³ = 137.03% increase
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