Find the value of \(\frac{cos^212&d

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

Find the value of \(\frac{cos^212°\;+\;cos^278°}{sin^290°}\) .

Options:

-1

Correct Answer:

Explanation:

Formula → [cos²A + cos²B = 1, when A + B = 90°]

Here, (27° + 63° = 90°), therefore,

⇒ \(\frac{cos^212°\;+\;cos^278°}{sin^290°}\)

= \(\frac{1}{1}\)

= 1