$\begin{bmatrix}1-x^2 & 2y\\x+5 & 0\end{bmatrix}=\begin{bmatrix} -3 & y-1\\7 & 0\end{bmatrix}$, then value of $(x-y)^2$ is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 9
$1-x^2=-3,x+5=7$
$x^2=4$
$x=±2$
$∴x=2$
$y-1=2y$
$y=-1$
$∴(x-y)^2=(2-(1))^2=3^2=9$