For what value(s) of x is A = […] is not a singular matrix

$\begin{bmatrix}\sqrt{2}x & 8 \\6 & \sqrt{2}x \end{bmatrix}=0⇒ 2x^2-48=0$

so $x=±2\sqrt{6}$

for \(R- \{2(\sqrt{6}),-2(\sqrt{6})\}\)

matrix is not singular