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If $2x, x + 4$ and $x + 1$ are in A.P., then the value of x is: |
6 $6\frac{1}{2}$ 7 8 |
7 |
In an A.P. difference between two consecutive term is same. Difference = ( 2nd term - 1st term ) = ( 3rd term - 2nd term ) ( x + 4 ) − 2x = ( x + 1 ) − ( x + 4 ) x + 4 − 2x = x + 1− x − 4 4−x = −3 x=7 So, the value of x is 7 |
