Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

The principal valus of $sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}$, is 

 

Options:

$\frac{\pi}{4}$

$\frac{-\pi}{4}$

$\frac{\pi}{2}$

$-\frac{\pi}{2}$

Correct Answer:

$-\frac{\pi}{2}$

Explanation:

$sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}= sin^{_1} (-1) = -\frac{\pi}{2}$