The principal valus of $sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}$, is
Answer & explanation
Correct answer: option 4
$sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}= sin^{_1} (-1) = -\frac{\pi}{2}$
The principal valus of $sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}$, is
Correct answer: option 4
$sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}= sin^{_1} (-1) = -\frac{\pi}{2}$