Practicing Success
The principal valus of $sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}$, is
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$\frac{\pi}{4}$ $\frac{-\pi}{4}$ $\frac{\pi}{2}$ $-\frac{\pi}{2}$ |
$-\frac{\pi}{2}$ |
$sin^{-1}\begin{Bmatrix}tan \left(-\frac{5\pi}{4}\right)\end{Bmatrix}= sin^{_1} (-1) = -\frac{\pi}{2}$ |