Simplify the following \(\frac{cosx-\sqrt {3}sinx}{2}\)

cos(\(\frac{π}{3}\)-x) cos(\(\frac{π}{3}\)+x) cos(\(\frac{π}{3}\)-x) 1

cos(\(\frac{π}{3}\)+x)

\(\frac{1}{2}\)cosx-\(\frac{\sqrt {3}}{2}\)sinx               = cos60° cosx - sin60° sinx         [π = 180°, \(\frac{π}{3}\)=60°] = cos(\(\frac{π}{3}+x\))        [cos(A + B)=cosA cosB - sinA sinB]