CUET Preparation Today
The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is : |
θ = tan-1 (2) θ = 45° θ = tan-1 (\(\frac{1}{4}\)) θ = tan-1 (4) |
θ = tan-1 (4) |
R = Hmax ⇒ $\frac{2 u^2 Sin \theta Cos \theta}{g} = \frac{u^2 Sin^2 \theta}{2g}$ tan θ = 4 ⇒ \(\theta\) =tan-1(4) |
