The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is :
Answer & explanation
Correct answer: option 4
R = Hmax
⇒ $\frac{2 u^2 Sin \theta Cos \theta}{g} = \frac{u^2 Sin^2 \theta}{2g}$
tan θ = 4 ⇒ \(\theta\) =tan-1(4)