CUET Preparation Today
If the system of equations \(x+ky-z=0,3x-ky-z=0\) and \(x-3y+z=0\) has non-zero solution, then \(k\) is |
\(-1\) \(0\) \(1\) \(2\) |
\(1\) |
Given the system is a homogeneous, so for non-zero solution determinant of the corresponding matrix should be nonzero. |
