CUET Preparation Today
CUET
-- Mathematics - Section A
Applications of Derivatives
If x=at2 and y=2at, then d2ydx2=
0
−1t2
−12at3
−t32a
The correct answer is Option (3) → −12at3
x=at2 and y=2at
dxdt=2at, dydt=2a⇒dydx=1t
d2ydx2=−1t2×dtdx
=−12at3