If the amplitude of the electric field of an electromagnetic wave is 9 V/m, the amplitude of its magnetic field will be
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 3.0 x 10−8 T
In an electromagnetic wave the field amplitudes are related through the speed of light.
\( \displaystyle B_0 = \frac{E_0}{c} \)
\( \displaystyle B_0 = \frac{9\,\mathrm{V\,m^{-1}}}{3\times10^{8}\,\mathrm{m\,s^{-1}}} = 3.0\times10^{-8}\,\mathrm{T} \)