A rectangular paper of width 8cm and length 22cm rolled along it width and a cylinder is formed. On the above Intimation, Solve the question given below |
If the outer surface area of cylinder is painted @ Rs.0.5/cm2, then the total cost of painting is |
₹88 ₹176 ₹78 ₹186 |
₹88 |
Here, in this case, some point is to be noted: 1. Length of the rectangle will becomes circumference of the base of the cylinder. 2. Breadth of the rectangle will becomes height of the cylinder. 3. Area of the rectangle will becomes curved surface area of the cylinder. ************************************************* According to the question: Area of the rectangle = l × b = 22 × 8 = 176 cm2 = Curved surface area of the cylinder. Cost of paint = Rs.0.5/cm2 Total cost of paint on the curved/outer surface area = curved surface area × cost per cm2 = 176 × 0.5 = ₹88 |