Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Chemical Kinetics

Question:

When the temperature changes from 293 K to 313 K, the rate of reaction

Options:

Remains same

Gets halved

Gets doubles

Gets quadruples

Correct Answer:

Gets quadruples

Explanation:

The correct answer is option 4. Gets quadruples.

Temperature is increased from \(293 K\) to \(313 K\)

Then \(n = \frac{313 -293}{10} = 2\)

Rate of reaction = \(2^n = 2^2 = 4\) times

Thus rate of reaction is quadrupled.