When the temperature changes from 293 K to 313 K, the rate of reaction |
Remains same Gets halved Gets doubles Gets quadruples |
Gets quadruples |
The correct answer is option 4. Gets quadruples. Temperature is increased from \(293 K\) to \(313 K\) Then \(n = \frac{313 -293}{10} = 2\) Rate of reaction = \(2^n = 2^2 = 4\) times Thus rate of reaction is quadrupled. |