$f(x)=\frac{x}{1+[x]}$, is discontinuous in set s, where s is
Answer & explanation
Correct answer: option 1
$f(x)=\frac{x}{1+n}$, n ≤ x < n + 1
(i) clearly, if n = −1 then f(x) is not defined
i.e. f(x) is not defined ∀ x ∈ [−1, 0)
(ii) if n ≠ −1
$f(x)=-\frac{x}{2}$; −3 ≤ x < −2 (n = −3)
= −x ; −2 ≤ x < −1 (n = −2)
= x ; 0 ≤ x < +1 (n = 0)
= ……….
………….
Clearly, the function is discontinuous at all integral values of x.
From (i) and (ii) f(x) is not continuous in set ‘S’
S = {[−1, 0) ∪ integers}.