Evaluate $\cos \left[ \cos^{-1} \left( -\frac{\sqrt{3}}{2} \right) + \frac{\pi}{6} \right]$. |
$1$ $0$ $-1$ $\frac{\sqrt{3}}{2}$ |
$-1$ |
The correct answer is Option (3) → $-1$ ## We have, $\cos \left[ \cos^{-1} \left( -\frac{\sqrt{3}}{2} \right) + \frac{\pi}{6} \right] = \cos \left[ \cos^{-1} \left( \cos \frac{5\pi}{6} \right) + \frac{\pi}{6} \right] \quad \left[ ∵\cos \frac{5\pi}{6} = -\frac{\sqrt{3}}{2} \right]$ $= \cos \left( \frac{5\pi}{6} + \frac{\pi}{6} \right) \quad [∵\cos^{-1} (\cos x) = x; \ x \in [0, \pi]]$ $= \cos \left( \frac{6\pi}{6} \right)$ $= \cos(\pi) = -1$ |