A vessel is full with 63 litres of milk. 9 litres milk is taken out and replaced by same amount of water and further 7 litres mixture is taken out and replaced by same amount of water. Find at the end of 2nd process the amount of water in the mixture?
Answer & explanation
Correct answer: option 3
i) \(\frac{9}{63}\) = \(\frac{1}{7}\) ⇒ Remaining part = \(\frac{6}{7}\),
ii) \(\frac{7}{63}\) = \(\frac{1}{9}\) ⇒ Remaining part = \(\frac{8}{9}\)
Now,
Milk after 2 process = 63 × \(\frac{6}{7}\) × \(\frac{8}{9}\) = 48 ltr.
∴ Water after 2 process = 63 - 48 = 15 Ltrs.