The three medians AX, BY and CZ of \(\triangle ABC\) meet at the point L. If the area of \(\triangle ABC\) is 42 cm2, what is the area of the quadrilateral BXLZ?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 14 cm2
The three medians divide a triangle into six small triangles of equal area. The quadrilateral BXLZ is made of two of them, \(\triangle BXL\) and \(\triangle BZL\).
Each small triangle \(\displaystyle=\frac{42}{6}=7\,\mathrm{cm^2}\)
Area of BXLZ \(=7+7=14\,\mathrm{cm^2}\)
