For a curve $\frac{(\text { Length of normal })^2}{(\text { Length of tangent })^2}$ is equal to
Answer & explanation
Correct answer: option 1
We have,
$\frac{(\text { Length of normal })^2}{(\text { Length of tangent })^2}=\left(\frac{d y}{d x}\right)^2$
$\Rightarrow \frac{(\text { Length of normal })^2}{(\text { Length of tangent })^2}=\frac{\text { Sub normal }}{\text { Sub tangent }}$