A can do 60% of a work in 18 days, while B can do 40% of the same work in 10 days. Both work together for 10 days only. C completed the remaining work in 4 days. In how many days will C complete the same work?
Answer & explanation
Correct answer: option 2
A = 60% of W = 18 days = 30 days,
B = 40% of W = 10 days = 25 days,
⇒ A + B worked for 10 days = (5 + 6) x 10 = 11 x 10 = 110 units, ..(Efficiency × Days = Total work)
⇒ Remaining work = 150 - 110 = 40 units,
⇒ C completed the remaining work in 4 days = \(\frac{40}{C}\) = 4 days,
⇒ C = 10, (Efficiency)
⇒ Time required for C to complete total work = \(\frac{150}{10}\) = 15 days ..(\(\frac{Work}{Efficiency}\) = Time)