if the volume of a sphere is 4,851 cm3, then what is its diameter (in cm) ?
( Take $\pi =\frac{22}{7}$)
Answer & explanation
Correct answer: option 4
We know that,
V = \(\frac{4}{3}\)πr3
We have,
Volume of sphere = 4,851 cm3
So,
= \(\frac{4}{3}\) × \(\frac{22}{7}\) × r3 = 4851
= r3 = 4851 × \(\frac{3}{4}\) × \(\frac{7}{22}\)
= r3 = 1157.625
= r = 10.5 cm
Diameter = 2 × r = 2 × 10.5 = 21 cm.