if the volume of a sphere is 4,851 cm³, then what is its diameter (in cm) ?

( Take $\pi =\frac{22}{7}$)

21

We know that,

V = \(\frac{4}{3}\)πr³

We have,

Volume of sphere = 4,851  cm³

So,

= \(\frac{4}{3}\) × \(\frac{22}{7}\) ×  r³ = 4851

= r³ = 4851 × \(\frac{3}{4}\) × \(\frac{7}{22}\) 

= r³ = 1157.625

= r = 10.5 cm

Diameter = 2 × r = 2 × 10.5 = 21 cm.