Practicing Success
If R is a relation on Z (set of all integers) defined by xRy, iff |x – y| ≤ 1, then (a) R is reflexive Choose the most appropriate answer from the options given below |
(a) and (d) only (a), (b) and (c) only (b) and (c) only (a), (b) and (e) only |
(a), (b) and (e) only |
|x - y| ≤ 1 → Relation on Z for every x ∈ Z ⇒ |x - x| = 0 ≤ 1 ⇒ (x, x) ∈ R reflexive for (x, y) ∈ R ⇒ |x - y| ≤ 1 ⇒ |y - x| ≤ 1 ⇒ (y, x) ∈ R symmetric for (x, y) ∈ R , (y, z) ∈ R ⇒ |x - y| ≤ 1 |y - z| ≤ 1 eg: (2, 1)∈ R (2, 3) ∈ R ⇒ |z - 1| ≤ 1 |2 - 3| ≤ 1 but |(1 - 3)| ≤ 1 (false) So it is not transitive Option: 4 |